1. Some zinc sulphate lechatelierites were heated to constant reparation with the following result crowd unneurotic of crucible=20.00g plenty of crucible& angstrom unitere; crystal=25.74gm fix of crucible& residure=23.22gm expect X in a formula ZnSO4XH2O from the data presumption above Solution fold of a crystal= push-down stack of crucible& crystal-Mass of acrusible = 25.74gm-20.00gm =5.74gm The down of ZnSO4XH2O =5.74gm Mass of residure=Mass of crucible& residure-Massof crusible =23.22gm-20.00gm 20.00gm Mass of residure=3.22gm demand the response below ZnSO4XH2O ZnSO4 + XH2O allow the molar atomic pile of ZnSO4XH2O to be Y Y of ZnSO4XH2O = 161gmol-1 But the mass of ZnSO4 = 3.22 NowY of ZnSO4XH2O =161gmol-1 of ZnSO4 =3.22gm Y= 287gmol-1 ZnSO4XH2O = 287gmol-1 Zn + S + O4 +X H2O = 287gmol-1 = (65+32+64+18X)gmol-1 Qn.1 18Xgmol-1 = (287- 161)gmol-1 X = 7 The summate of water molecule is 7 Qn.2 What wad of Oxygen botch up at s.t.p will be obtained by decomposition of 4.32g of Mercury(II)oxide(H O) by heat Solution Data given:Mass of Mercury(II)oxide=4.32gm Volume of Oxygen(O2)=? date the reply below Hgos 2Hg + O2g 2moles of HgO produces 1mole of O2g 1mole of any gas at s.t.p = 22.
4dm3 Molar mass of HgO =201gmol-1 +16gmol-1 =217gmol-1 2(217gmol-1)of HgO = 22.4dm3 4.32gm of HgO = ? = 0.22229774dm3 or 222.96774cm3 The volume of oxygen at s.t.p is 222.96774cm3 or 0.22296774dm3 Qn.3 What volume in cm3 of Hydrogen at s.t.p would be required to hydrogenate 6.5gm of alkyne to Ethene? (H=1.0,C=12.0& vapourised molar volume at s.t.p =22.4) solution data given Mass of ethyne = 6.5gm Volume of ethane = ? get the reaction below CHCH + H2 CH2CH2 26gmol-1 of CHCH = 22400cm3mol-1 of H2g 6.5gm of CHCH = ? =...If you pauperization to get a tolerable essay, order it on our website: Ordercustompaper.com
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